document.write( "Question 1050192: while at the post office Mrs. Adams purchased $2.39 worth of stamps. The number of 3 cent stamps exceeded four times the number of 6 cent stamps by 1. Also the number of 3 cent stamps was 13 less than the number 2 cent stamps. How many of each kind did she purchase? \n" ); document.write( "

Algebra.Com's Answer #665876 by jorel555(1290) $\"\"$ $\"About$

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Let n be the number of 6-cent stamps. Then 3-cent stamps are 4n+1, and 2-cent stamps are (4n+1)+13:4n+14. So:
\n" ); document.write( "6n+3(4n+1)+2(4n+14)=239
\n" ); document.write( "26n+31=239
\n" ); document.write( "26n=208
\n" ); document.write( "n=8
\n" ); document.write( "Mrs. Adams bought 8 6-cent stamps,33 3-cent stamps, and 46 2-cent stamps. ☺☺☺☺ \n" ); document.write( "

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