document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=91717>Question 91717</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Need help with the following - Thank you\r<BR>\n" );
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document.write( "160^1/2 - 10^1/2\r<BR>\n" );
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document.write( "-7x^3/5 - 8x^3/5<BR>\n" );
document.write( "thanks<BR>\n" );
document.write( "llo </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #66587 by </B><A HREF=/tutors/aboutme.mpl?userid=jayanthihemkos@yahoo.com><B>jayanthihemkos@yahoo.com(87)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jayanthihemkos@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=66587\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 160^1/2 - 10^1/2\r<BR>\n" );
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document.write( "since both the terms have same root, we can write as \r<BR>\n" );
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document.write( "(160-10)^1/2\r<BR>\n" );
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document.write( "150^1/2  \r<BR>\n" );
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document.write( "(25*6)^1/2   (150 can be split as 25*6)\r<BR>\n" );
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document.write( "square root of 25 is 5 , that is taken out\r<BR>\n" );
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document.write( "5*(6)^1/2\r<BR>\n" );
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document.write( "5*6*1.414( value of square root of 2 is 1.414)\r<BR>\n" );
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document.write( "42.42\r<BR>\n" );
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document.write( "2) -7x^3/5 - 8x^3/5\r<BR>\n" );
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document.write( "here x^3/5 is common between the two terms\r<BR>\n" );
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document.write( "Taking the common factor , we have\r<BR>\n" );
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document.write( " ( -7-8)x^3/5\r<BR>\n" );
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document.write( "-15x^3/5\r<BR>\n" );
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document.write( " Hence the solution\r<BR>\n" );
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document.write( " </SPAN>\n" );
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