document.write( "Question 1050121: I am thinking of two numbers. The sum of the first and twice the second is 34. The difference of the first and four times the second is 4. What are the numbers? \n" ); document.write( "

Algebra.Com's Answer #665704 by advanced_Learner(501) $\"\"$ $\"About$

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x+y=34
\n" ); document.write( "x-4y=4\r
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Solved by pluggable solver: SOLVE linear system by SUBSTITUTION

Solve:
\n" ); document.write( " $\"+system%28+%0D%0A++++1%5Cx+%2B+1%5Cy+=+34%2C%0D%0A++++1%5Cx+%2B+-4%5Cy+=+4+%29%0D%0A++\"$ We'll use substitution. After moving 1*y to the right, we get:
\n" ); document.write( " $\"1%2Ax+=+34+-+1%2Ay\"$ , or $\"x+=+34%2F1+-+1%2Ay%2F1\"$ . Substitute that
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\n" ); document.write( " $\"1%2A%2834%2F1+-+1%2Ay%2F1%29+%2B+-4%5Cy+=+4\"$ and simplify: So, we know that y=6. Since $\"x+=+34%2F1+-+1%2Ay%2F1\"$ , x=28.
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\n" ); document.write( " Answer: $\"system%28+x=28%2C+y=6+%29\"$ .
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