document.write( "Question 1050048: A local water park has two types of season passes. Plan A costs a one time fee of $131 for admission plus $5 for every parking trip. Plan B costs a one-time fee of $50 for parking plus $20 for admission every trip. How many trips must a person make for plan A and plan B to be equal in value? \n" ); document.write( "
Algebra.Com's Answer #665638 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! let x be the number of trips, then \n" ); document.write( ": \n" ); document.write( "Plan A cost is 131 + 5x \n" ); document.write( ": \n" ); document.write( "Plan B cost is 20x + 50 \n" ); document.write( ": \n" ); document.write( "we set Plan A = to Plan B and solve for x \n" ); document.write( ": \n" ); document.write( "131 + 5x = 20x + 50 \n" ); document.write( ": \n" ); document.write( "15x = 81 \n" ); document.write( ": \n" ); document.write( "************* \n" ); document.write( "x = 5.4 trips \n" ); document.write( "************* \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " |