document.write( "Question 1050027: y=3(x-2)^2+3 y=6x-12
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Algebra.Com's Answer #665609 by ikleyn(52781) $\"\"$ $\"About$

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document.write( "y = 3(x-2)^2 + 3,   (1)\r\n" );
document.write( "y = 6x - 12.        (2)\r\n" );
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document.write( "The expression (2) for y = 6x-12 substitute into the left side of (1) insead of y. You will get\r\n" );
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document.write( "6x - 12 = 3(x_2)^2 +3.   (3)\r\n" );
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document.write( "It is single quadratic equation for x.\r\n" );
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document.write( "Simplify and solve it by any appropriate method (quadratic formula or factoring).\r\n" );
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document.write( "That's all.\r\n" );
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document.write( "You can express it in other words:\r\n" );
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document.write( "Since the left sides of equations (1) and (2) are identical, their right sides are equal:\r\n" );
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document.write( "6x - 12 = 3(x_2)^2 +3.  (4)\r\n" );
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document.write( "It is the same equation as (1).\r\n" );
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document.write( "The continuation is the same.\r\n" );
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