document.write( "Question 1049998: Find the equation for the line that passes through the point (5,4), and that is perpendicular to the line with the equation x=4 \n" ); document.write( "
Algebra.Com's Answer #665585 by MathLover1(20850)\"\" \"About 
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\"x+=+4\" is a \"vertical\" line.\r
\n" ); document.write( "\n" ); document.write( "recall: \"y=mx%2Bb\" where \"m+=+slope\" and\r
\n" ); document.write( "\n" ); document.write( "\"m+=+%28change_+in_+y%29+%2F+%28change_+in_+x%29\"\r
\n" ); document.write( "\n" ); document.write( "if the slope is \"undefined\" because there is \"no\" change in '\"x\"', which is equivalent to dividing by \"0\"\r
\n" ); document.write( "\n" ); document.write( "A line \"perpendicular\" to a \"vertical\" line is a \"horizontal\" line.\r
\n" ); document.write( "\n" ); document.write( " There is \"no\" change in '\"y\"', so its slope is \"0\".\r
\n" ); document.write( "\n" ); document.write( "so, \"y=mx%2Bb\" ...plug in the coordinates of given point (\"5\",\"4\") and slope \"m=0\"\r
\n" ); document.write( "\n" ); document.write( "\"y=mx%2Bb\"\r
\n" ); document.write( "\n" ); document.write( "\"4=0%2A5%2Bb\"\r
\n" ); document.write( "\n" ); document.write( "\"4=b\"\r
\n" ); document.write( "\n" ); document.write( "so, for a horizontal line to go through the point (\"5\",\"4\"), we simply set \"y+=+b\" or:\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28y=4%29\"\r
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