document.write( "Question 1049842: Let ƒ(x)=e−(x+1)2.
\n" ); document.write( " Draw a graph of the function on the interval [-3,3] and estimate from the graph whether ƒ′(−1) is positive or negative or zero, and whether ƒ′′(−1) is positive, negative or zero.
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Algebra.Com's Answer #665524 by advanced_Learner(501)\"\" \"About 
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f` is \r
\n" ); document.write( "\n" ); document.write( "\"e%5E%28-x%5E2-2x-1%29%2A%28-2x-2%29\"\r
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\n" ); document.write( "\n" ); document.write( "f`(-1)=1
\n" ); document.write( "f``(-1)=2\r
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\n" ); document.write( "\n" ); document.write( "first deriv=\"e%5E%28-x%5E2-2x-1%29%2A%28-2x-2%29\" at x=-1
\n" ); document.write( "first deriv=\"e%5E%28-1%2B2-1%29%2A%282-2%29\" at x=\"-1\"
\n" ); document.write( "first deriv=\"e%5E%280%29%2A%280%29\" at x=\"-1\"\r
\n" ); document.write( "\n" ); document.write( "first derivative is \"1\" at x=\"-1\"\r
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\n" ); document.write( "\n" ); document.write( "second derivative=\"e%5E%28-x%5E2-2x-1%29%2A%28-2x-2%29\" at x=\"-1\"\r
\n" ); document.write( "\n" ); document.write( "second derivative=
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\n" ); document.write( "xat x=\"-1\"\r
\n" ); document.write( "\n" ); document.write( "second deriv=\"e%5E%28-1%2B2-1%29%2A%282-2%29%2A%282-2%29%2Be%5E%28-1%2B2-1%29%2A%282-2%29%2A%28-2%29\"
\n" ); document.write( "second deriv=\"e%5E%280%29%2A%280%29%2A%280%29%2Be%5E%280%29%2A%280%29%2A%28-2%29\"
\n" ); document.write( "second deriv=\"e%5E%280%29%2Be%5E%280%29\"
\n" ); document.write( "second deriv is \"2\" at x=\"-1\"\r
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