document.write( "Question 1049893: Prove that the roots of quadratic equation i.e ax2+bx+c=0 numerically equals but opposite in sign to the roots of ax2-bx+c \n" ); document.write( "
Algebra.Com's Answer #665490 by advanced_Learner(501)\"\" \"About 
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\"ax%5E2%2Bbx%2Bc\"=\"0\"
\n" ); document.write( "\"x%5E2%2B%28b%2Fa%29x%2Bc%2F%28a%29\"=\"0\"
\n" ); document.write( "\"x%5E2%2B%28b%2Fa%29x\"=\"-c%2Fa\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B%28b%2Fa%29x%2B%28b%2F2a%29%5E2\"=\"-c%2Fa\"+\"%28b%2F2a%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x%2Bb%2F2a%29%5E2\"=\"-c%2Fa\"+\"%28b%2F2a%29%5E2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%28x%29=+-b%2F2a+%2B-+sqrt%28-c%2Fa%2B%28b%2F2a%29%5E2%29\"
\n" ); document.write( "\r
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+-4%2Aa%2Ac%2Bb%5E2+%29%29%2F%282%2Aa%29%29+\"
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"\r
\n" ); document.write( "\n" ); document.write( "\"ax%5E2-bx%2Bc\"=\"0\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%5E2-%28b%2Fa%29x%2Bc%2F%28a%29\"=\"0\"
\n" ); document.write( "\"x%5E2-%28b%2Fa%29x\"=\"-c%2Fa\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%5E2-%28b%2Fa%29x%2B%28b%2F2a%29%5E2\"=\"-c%2Fa\"+\"%28b%2F2a%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x-b%2F2a%29%5E2\"=\"-c%2Fa\"+\"%28b%2F2a%29%5E2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%28x%29=+b%2F2a+%2B-+sqrt%28-c%2Fa%2B%28b%2F2a%29%5E2%29\"
\n" ); document.write( "\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%28b+%2B-+sqrt%28+-4%2Aa%2Ac%2Bb%5E2+%29%29%2F%282%2Aa%29%29+\"
\n" ); document.write( "\"x+=+%28b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"\r
\n" ); document.write( "\n" ); document.write( "hence proved
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