document.write( "Question 1049918: The sum of the ages of two cosins is 15. In 3 years the older cousin will be twice as old as the younger cousin. How old is the cousin now? \n" ); document.write( "

Algebra.Com's Answer #665487 by jorel555(1290) $\"\"$ $\"About$

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Let m and n represent the two cousins. Then m+n=15. In three years n will be twice as old as m, so 2(m+3)=n+3. So:
\n" ); document.write( "2m+6=n+3
\n" ); document.write( "2m+3=n
\n" ); document.write( "m+2m+3=15
\n" ); document.write( "3m=12
\n" ); document.write( "m=4
\n" ); document.write( "n=11
\n" ); document.write( "The older cousin is now 11 years old. ☺☺☺☺ \n" ); document.write( "

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