document.write( "Question 1049902: The product of two numbers is 96. One number is 4 more than the other number. Find the two numbers. \n" ); document.write( "
Algebra.Com's Answer #665459 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "let numbers be \"x\" and \"y\"\r
\n" ); document.write( "\n" ); document.write( "if the product of two numbers is \"96\", we have\r
\n" ); document.write( "\n" ); document.write( "\"xy=96\"........solve for \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"x=96%2Fy\"...............eq.1\r
\n" ); document.write( "\n" ); document.write( "if one number is \"4\" more than the other number, we have\r
\n" ); document.write( "\n" ); document.write( "\"x=y%2B4\".........eq.2\r
\n" ); document.write( "\n" ); document.write( "from eq.1 and eq.2 we have\r
\n" ); document.write( "\n" ); document.write( "\"96%2Fy=y%2B4\"........solve for \"y\"\r
\n" ); document.write( "\n" ); document.write( "\"96=y%28y%2B4%29\"\r
\n" ); document.write( "\n" ); document.write( "\"96=y%5E2%2B4y\"\r
\n" ); document.write( "\n" ); document.write( "\"y%5E2%2B4y-96=0\".............use quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"y+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"...since \"a=1\",\"b=4\", and \"c=-96\" we have\r
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\n" ); document.write( "\n" ); document.write( "\"y+=+%28-4+%2B-+sqrt%28+4%5E2-4%2A1%2A%28-96%29+%29%29%2F%282%2A1%29+\"\r
\n" ); document.write( "\n" ); document.write( "\"y+=+%28-4+%2B-+sqrt%28+16%2B384+%29%29%2F2+\"\r
\n" ); document.write( "\n" ); document.write( "\"y+=+%28-4+%2B-+sqrt%28+400+%29%29%2F2+\"\r
\n" ); document.write( "\n" ); document.write( "\"y+=+%28-4+%2B-+20%29%2F2+\"\r
\n" ); document.write( "\n" ); document.write( "\"y+=+%28-cross%284%292+%2B-+cross%2820%2910%29%2Fcross%282%291+\"\r
\n" ); document.write( "\n" ); document.write( "\"y+=+%28-2+%2B-+10%29+\"\r
\n" ); document.write( "\n" ); document.write( "solutions:\r
\n" ); document.write( "\n" ); document.write( "\"y+=+-2+%2B+10+\"->\"y+=+8+\"
\n" ); document.write( "or
\n" ); document.write( "\"y+=+-2-+10+\"->\"y+=+-12+\"\r
\n" ); document.write( "\n" ); document.write( "now find corresponding \"x\" for each \"y\"\r
\n" ); document.write( "\n" ); document.write( "\"x=y%2B4\".........eq.2...if \"y+=+8+\"\r
\n" ); document.write( "\n" ); document.write( "\"x=8%2B4\"
\n" ); document.write( "\"x=12\"\r
\n" ); document.write( "\n" ); document.write( "\"x=y%2B4\".........eq.2...if \"y+=+-12+\"\r
\n" ); document.write( "\n" ); document.write( "\"x=-12%2B4\"
\n" ); document.write( "\"x=-8\"\r
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\n" ); document.write( "\n" ); document.write( "so, we have two solutions:\r
\n" ); document.write( "\n" ); document.write( "1.\"x=12\" and \"y+=+8+\"
\n" ); document.write( "2.\"x=-8\" and \"y+=+-12+\"\r
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