document.write( "Question 1049827: One number is 4 more than another. The difference between their squares is 104. What are the numbers? \n" ); document.write( "
Algebra.Com's Answer #665419 by addingup(3677)\"\" \"About 
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Let the numbers be x and y
\n" ); document.write( "x = y+4
\n" ); document.write( "x^2-y^2 = 104 Substitute for x:
\n" ); document.write( "(y+4)^2-y^2 = 104
\n" ); document.write( "Expand the left side with FOIL (First-Outer-Inner-Last)
\n" ); document.write( "(y^2+8y+16)-y^2 = 104
\n" ); document.write( "8y+(y^2-y^2)+16 = 104
\n" ); document.write( "8y+16 = 104
\n" ); document.write( "8y = 88
\n" ); document.write( "y = 11
\n" ); document.write( "Since x = y+4 = x = 11+4= 15
\n" ); document.write( "Now we have:
\n" ); document.write( "y = 11
\n" ); document.write( "x = 15
\n" ); document.write( ">>>>>>>>>>>>>>>>
\n" ); document.write( "Check:
\n" ); document.write( "x^2-y^2 = 104
\n" ); document.write( "15^2-11^2 = 104
\n" ); document.write( "225-121 = 104 Correct
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