document.write( "Question 1049512: A bus company has 4000 passengers daily, each paying a fare of $2. For each $0.15 increase, the company estimates that it will lose 40 passengers per day. If the company needs to have a revenue of $10 450 per day to stay in business, what fare should be charged?\r
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document.write( "(Functions Math) \n" );
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Algebra.Com's Answer #665396 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A bus company has 4000 passengers daily, each paying a fare of $2. \n" ); document.write( " For each $0.15 increase, the company estimates that it will lose 40 passengers per day. \n" ); document.write( " If the company needs to have a revenue of $10,450 per day to stay in business, what fare should be charged? \n" ); document.write( ": \n" ); document.write( "Rev = no. of pass * fare \n" ); document.write( "the equation for this situation \n" ); document.write( ": \n" ); document.write( "let x = the no. of .15 increases and = no. of 40 passenger decreases\r \n" ); document.write( "\n" ); document.write( "(4000-40x)(2+.15x) = 10450 \n" ); document.write( "FOIL \n" ); document.write( "8000 + 600x - 80x - 6x^2 = 10450 \n" ); document.write( "Combine like terms to form a quadratic equation \n" ); document.write( "-6x^2 + 520x + 8000 - 10450 = 0 \n" ); document.write( "-6x^2 + 520x - 2450 = 0 \n" ); document.write( " solve this using the quadratic formula. a=-6; b=520; c=-2450 \n" ); document.write( "I got two solutions \n" ); document.write( "x = 81 \n" ); document.write( "and \n" ); document.write( "x = 5, this is the reasonable solution. 5 price increases will yield $10,450 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "See if that's true \n" ); document.write( "5 price increases: 5(.15) + 2 = $2.75 is the fare \n" ); document.write( "5 40 pass decreases: 4000 - 5(40) = 3800 passengers \n" ); document.write( "Rev = 2.75 * 3800 = $10,450 \n" ); document.write( " |