document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1049742>Question 1049742</A>: <I><SPAN STYLE=\"word-break: break-all;\"> f(x)=1/1-x<BR>\n" );
document.write( "find:<BR>\n" );
document.write( "1.f'(0)<BR>\n" );
document.write( "2.f\"(0)<BR>\n" );
document.write( "3.f\"'(0) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #665296 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=665296\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Using the Division Rule:<BR>\n" );
document.write( "f = 1/(1-x)<BR>\n" );
document.write( "1) f' = [0 - 1(-1)]/(1-x)^2 = 1/(1-x)^2 , f'(0) = 1<BR>\n" );
document.write( "2) f\" = [0 - (-1)2(1-x)]/(1-x)^4 = -2(1-x)/ (1-x)^4  = -2/(1-x)^3 , f\"(0) = -2<BR>\n" );
document.write( "3) f'\" = [0 - (-2)3(1-x)^2]/(1-x)^6 = -6(1-x)^2/ (1-x)^6  = -6/(1-x)^4, f\"'(0) = -6 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );