document.write( "Question 1049702: Consider the function f(x) = e^rx. Determine the values of r so that f sasisfies the equation f\"(x) + f'(x)−6f(x) = 0.
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Algebra.Com's Answer #665278 by advanced_Learner(501)\"\" \"About 
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Consider the function \"f%28x%29\" = \"e%5Erx\". Determine the values of r so that f satisfies the equation f\"(x) + f'(x)-6f(x) = 0\r
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\n" ); document.write( "\n" ); document.write( "f'(x)=\"r%2Ae%5Erx\"
\n" ); document.write( "f\"(x)=\"r%5E2%2Ae%5Erx\"\r
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\n" ); document.write( "\n" ); document.write( "f\"(x) + f'(x)-6f(x) = 0
\n" ); document.write( "\"r%5E2%2Ae%5Erx\"+\"r%2Ae%5Erx\"-6\"e%5Erx\"=\"0\"
\n" ); document.write( "\"e%5Erx\"*\"%28r%5E2%2Br-6%29\"=\"0\"\r
\n" ); document.write( "\n" ); document.write( "\"e%5Erx\"=\"0\" and \"r%5E2%2Br-6\"=\"0\"\r
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ar%5E2%2Bbr%2Bc=0\" (in our case \"1r%5E2%2B1r%2B-6+=+0\") has the following solutons:
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\n" ); document.write( " \"r%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%281%29%5E2-4%2A1%2A-6=25\".
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\n" ); document.write( " Discriminant d=25 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-1%2B-sqrt%28+25+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"r%5B1%5D+=+%28-%281%29%2Bsqrt%28+25+%29%29%2F2%5C1+=+2\"
\n" ); document.write( " \"r%5B2%5D+=+%28-%281%29-sqrt%28+25+%29%29%2F2%5C1+=+-3\"
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\n" ); document.write( " Quadratic expression \"1r%5E2%2B1r%2B-6\" can be factored:
\n" ); document.write( " \"1r%5E2%2B1r%2B-6+=+1%28r-2%29%2A%28r--3%29\"
\n" ); document.write( " Again, the answer is: 2, -3.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B1%2Ax%2B-6+%29\"

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\n" ); document.write( "\"r\"=\"-3\"
\n" ); document.write( "\"r\"=\"2\"
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