document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1049706>Question 1049706</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the equation of the tangent line to the curve of x^2 + 3xy + y^2 = 5 at (1,1) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #665271 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=665271\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Implicit Differentiation:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x%2B3%281%2Ay%2Bx%28dy%2Fdx%29%29%2B2y%2A%28dy%2Fdx%29=0 ALIGN=MIDDLE  ALT=\"2x%2B3%281%2Ay%2Bx%28dy%2Fdx%29%29%2B2y%2A%28dy%2Fdx%29=0\"   DISABLED_style= \"max-width:90%; height:auto;\" >----------used quotient rule<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x%2B3y%2B3x%28dy%2Fdx%29%2B2y%28dy%2Fdx%29=0 ALIGN=MIDDLE  ALT=\"2x%2B3y%2B3x%28dy%2Fdx%29%2B2y%28dy%2Fdx%29=0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%283x%2B2y%29%28dy%2Fdx%29=-2x-3y ALIGN=MIDDLE  ALT=\"%283x%2B2y%29%28dy%2Fdx%29=-2x-3y\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28dy%2Fdx=-%282x%2B3y%29%2F%283x%2B2y%29%29 ALIGN=MIDDLE  ALT=\"highlight%28dy%2Fdx=-%282x%2B3y%29%2F%283x%2B2y%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "This rate of change as a slope value at (1,1) is:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-%285%2F5%29 ALIGN=MIDDLE  ALT=\"-%285%2F5%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28-1%29 ALIGN=MIDDLE  ALT=\"highlight%28-1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "Assumption is that point  (1,1) is on the curve given.  The equation for line tangent to the curve at (1,1) easily found using the point-slope equation form:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y-1=-1%28x-1%29 ALIGN=MIDDLE  ALT=\"y-1=-1%28x-1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=-x%2B1%2B1 ALIGN=MIDDLE  ALT=\"y=-x%2B1%2B1\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28y=-x%2B2%29 ALIGN=MIDDLE  ALT=\"highlight%28y=-x%2B2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >---------in slope-intercept form </SPAN>\n" );
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