document.write( "Question 1049577: Two investments totaling
\n" ); document.write( "$56,000 produce an annual income of $1400. One investment yields
\n" ); document.write( "4% per year, while the other yields
\n" ); document.write( "2% per year. How much is invested at each rate?
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Algebra.Com's Answer #665223 by ankor@dixie-net.com(22740)\"\" \"About 
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Two investments totaling $56,000 produce an annual income of $1400.
\n" ); document.write( " One investment yields 4% per year, while the other yields 2% per year.
\n" ); document.write( " How much is invested at each rate?
\n" ); document.write( ":
\n" ); document.write( "let x = amt invested at 4%
\n" ); document.write( "the total of the 2 investments is $56,000, therefor:
\n" ); document.write( "(56000-x) = amt invested at 2%
\n" ); document.write( ":
\n" ); document.write( "Total interest equation
\n" ); document.write( ".04x + .02(56000-x) = 1400
\n" ); document.write( ".04x + 1120 - .02x = 1400
\n" ); document.write( ".04x - .02x = 1400 - 1120
\n" ); document.write( ".02x = 280
\n" ); document.write( "x = 280/.02
\n" ); document.write( "x = $14000 invested at 4%
\n" ); document.write( ":
\n" ); document.write( "I'll let you find the amt invested a 2%.
\n" ); document.write( "Check your solutions by finding the sum of the actual amt invested in each
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