document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1049619>Question 1049619</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The simple interest on a certain sum  of money for 3 years at 12% p.a is Rs 6750. What will be the compound interest on that sum at the same rate for the same period ?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #665202 by </B><A HREF=/tutors/aboutme.mpl?userid=satyareddy22><B>satyareddy22(84)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=satyareddy22><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=665202\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> S.I = (PTR/100)<BR>\n" );
document.write( "S.I = 6750 ,T=3YRS,R=12%,p=?<BR>\n" );
document.write( "SUBSTITUTING ALL VALUES IN THE ABOVE FORMULA<BR>\n" );
document.write( "WE GET,P = 18750<BR>\n" );
document.write( "NOW, A = P(1+R/100)^T<BR>\n" );
document.write( "P=18750, T=3YRS,R = 12%<BR>\n" );
document.write( "A= 18750(1+12/100)^3<BR>\n" );
document.write( " = 18750(28/25)^3<BR>\n" );
document.write( " =26342.4<BR>\n" );
document.write( "NOW C.I = A - P<BR>\n" );
document.write( "        = 26342.4-18750=7592.4<BR>\n" );
document.write( "SO,C.I = 7592.4 </SPAN>\n" );
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