document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1049605>Question 1049605</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The four term of a G.p is 56 while the six term is 7/8.Find the G.p and hence sum to infinity<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #665197 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=665197\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The four term of a G.p is 56 while the six term is 7/8.Find the G.p and hence sum to infinity<BR>\n" );
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document.write( "g(4) = a*r^3 = 56<BR>\n" );
document.write( "g(6) = a*r^5 = 7/8<BR>\n" );
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document.write( "Divide g(6) by g(4) to get r^2 = (7/8)/56 = 1/(8^2) <BR>\n" );
document.write( "r = 1/8<BR>\n" );
document.write( "Solve for \"a\"::<BR>\n" );
document.write( "a*r^3 = 56<BR>\n" );
document.write( "a = 56/(1/8)^3 = 28672<BR>\n" );
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document.write( "Sum to infinity:: = a/(1-r) = 28673/(7/8) = 32768<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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