document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1049517>Question 1049517</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two friends live 1.1 miles apart along the same road. If they walk toward each other at rates that differ by 1/2 mph and they meet 12 minutes later, how fast is each person walking? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #665100 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=665100\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let n be the slower walker. Then:<BR>\n" );
document.write( "1/5(n)+1/5(n+1/2)=11/10<BR>\n" );
document.write( "2n+2(n+1/2)=11<BR>\n" );
document.write( "4n+1=11<BR>\n" );
document.write( "4n=10<BR>\n" );
document.write( "n=2.5 mph<BR>\n" );
document.write( "n+1/2=3 mph. &#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
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