document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1049483>Question 1049483</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given: &#8736;A is comp. to &#8736;B<BR>\n" );
document.write( "&#8736;C is comp. to &#8736;B<BR>\n" );
document.write( "&#8736;A = (3x+y)°<BR>\n" );
document.write( "&#8736;B = (x+4y+2)°<BR>\n" );
document.write( "&#8736;C = (3y-3)°<BR>\n" );
document.write( "Find: m&#8736;B\r<BR>\n" );
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document.write( "(comp. = complementary)\r<BR>\n" );
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document.write( "I was thinking that since complementary angles are (90-x) you would figure out what x is by possibly adding angle A angle B and angle C all together and solving... I'm not sure if this is right. Would you use solving systems? I was thinking maybe you would because there's x and y you need to solve for. I am having a hard time understanding this concept. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #665075 by </B><A HREF=/tutors/aboutme.mpl?userid=hussamuddin><B>hussamuddin(51)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=hussamuddin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=665075\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> you are right, go ahead </SPAN>\n" );
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