document.write( "Question 1049515: Given the quadratic equation y= -2x^2 - 16x- 33 and a line with slope -2 have just one point of intersection, what is the y-intercept of the line? \n" ); document.write( "

Algebra.Com's Answer #665073 by ewatrrr(24785) $\"\"$ $\"About$

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Line y = $\"highlight_green%28-2%29x+%2B+b\"$
\n" ); document.write( "tangent to:
\n" ); document.write( "f(x)= -2x^2 - 16x- 33
\n" ); document.write( "f' = -4x - 16 = slope of tangent line
\n" ); document.write( "-2 = -4x - 16
\n" ); document.write( "x = -7/2
\n" ); document.write( "f(-7/2) = -3/2
\n" ); document.write( "P(-7/2, -3/2) Point of Intersection
\n" ); document.write( "***Using point-slope form, $\"y+-+y%5B1%5D+=+highlight_green%28m%29%28x+-+x%5B1%5D%29\"$
\n" ); document.write( "y + 3/2= -2(x+7/2)
\n" ); document.write( "y = -2x -17/2\r
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