document.write( "Question 1049501: Find the coordinates of the vertices of the figure formed by the system of inequalities\r
\n" ); document.write( "\n" ); document.write( "x + y ≤ 2
\n" ); document.write( "x - 2y ≤ 8
\n" ); document.write( "x + (-1/3)y ≥ -2/3
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Algebra.Com's Answer #665060 by stanbon(75887)\"\" \"About 
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Find the coordinates of the vertices of the figure formed by the system of inequalities
\n" ); document.write( "1st:: x + y ≤ 2
\n" ); document.write( "2nd:: x - 2y ≤ 8
\n" ); document.write( "3rd:: x + (-1/3)y ≥ -2/3
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\n" ); document.write( "1st:: y <= -x+2
\n" ); document.write( "2nd: y >= (x-8)/2
\n" ); document.write( "3rd:: y <= (x+(2/3))/(1/3)
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\n" ); document.write( "Intersection of 1st and 2nd::
\n" ); document.write( "-x+2 = (x/2) - 4
\n" ); document.write( "(3/2)x = 6
\n" ); document.write( "x = 4
\n" ); document.write( "y = -x+2 = -2
\n" ); document.write( "Vertex:: (4,-2)
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\n" ); document.write( "Intersection of 1st and 3rd::
\n" ); document.write( "-x+2 = 3x + 2
\n" ); document.write( "4x = 0
\n" ); document.write( "x = 0
\n" ); document.write( "y = -x+2 = 2
\n" ); document.write( "Vertex:: (0,2)
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\n" ); document.write( "Intersection of 2nd and 3rd::
\n" ); document.write( "(x/2)-4 = 3x+2
\n" ); document.write( "(5/2)x = -6
\n" ); document.write( "x = -12/5 = -(2 2/5)
\n" ); document.write( "y = 3x+2 = 3(-12/5)+(10/5) = -26/5 = -(5 1/5)
\n" ); document.write( "Vertex:: (-12/5,-26/5)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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