document.write( "Question 1049501: Find the coordinates of the vertices of the figure formed by the system of inequalities\r
\n" );
document.write( "\n" );
document.write( "x + y ≤ 2
\n" );
document.write( "x - 2y ≤ 8
\n" );
document.write( "x + (-1/3)y ≥ -2/3
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #665060 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Find the coordinates of the vertices of the figure formed by the system of inequalities \n" ); document.write( "1st:: x + y ≤ 2 \n" ); document.write( "2nd:: x - 2y ≤ 8 \n" ); document.write( "3rd:: x + (-1/3)y ≥ -2/3 \n" ); document.write( "------ \n" ); document.write( "1st:: y <= -x+2 \n" ); document.write( "2nd: y >= (x-8)/2 \n" ); document.write( "3rd:: y <= (x+(2/3))/(1/3) \n" ); document.write( "-------------------------------- \n" ); document.write( "Intersection of 1st and 2nd:: \n" ); document.write( "-x+2 = (x/2) - 4 \n" ); document.write( "(3/2)x = 6 \n" ); document.write( "x = 4 \n" ); document.write( "y = -x+2 = -2 \n" ); document.write( "Vertex:: (4,-2) \n" ); document.write( "----------------- \n" ); document.write( "Intersection of 1st and 3rd:: \n" ); document.write( "-x+2 = 3x + 2 \n" ); document.write( "4x = 0 \n" ); document.write( "x = 0 \n" ); document.write( "y = -x+2 = 2 \n" ); document.write( "Vertex:: (0,2) \n" ); document.write( "---- \n" ); document.write( "Intersection of 2nd and 3rd:: \n" ); document.write( "(x/2)-4 = 3x+2 \n" ); document.write( "(5/2)x = -6 \n" ); document.write( "x = -12/5 = -(2 2/5) \n" ); document.write( "y = 3x+2 = 3(-12/5)+(10/5) = -26/5 = -(5 1/5) \n" ); document.write( "Vertex:: (-12/5,-26/5) \n" ); document.write( "------------ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "---------- \n" ); document.write( " |