document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=91567>Question 91567</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve each of the following systems by substitution:\r<BR>\n" );
document.write( "\n" );
document.write( "5x-2y=-5<BR>\n" );
document.write( "y-5x=3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #66502 by </B><A HREF=/tutors/aboutme.mpl?userid=uma><B>uma(370)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=uma><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=66502\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5x-2y=-5----------(1)<BR>\n" );
document.write( "y-5x=3<BR>\n" );
document.write( "==> y = 5x+3 [adding 5x to both the sides]\r<BR>\n" );
document.write( "\n" );
document.write( "substituting this value in (1), we get,\r<BR>\n" );
document.write( "\n" );
document.write( "5x - 2(3+5x)= -5<BR>\n" );
document.write( "==> 5x - 6 - 10x = -5<BR>\n" );
document.write( "==> -5x = -5+6\r<BR>\n" );
document.write( "\n" );
document.write( "==> -5x = 1<BR>\n" );
document.write( "==> x = 1/-5\r<BR>\n" );
document.write( "\n" );
document.write( "==> x = -1/5<BR>\n" );
document.write( "So y = 5x+3<BR>\n" );
document.write( "     = 5(-1/5)+3<BR>\n" );
document.write( "     = -1+3<BR>\n" );
document.write( "     = 2\r<BR>\n" );
document.write( "\n" );
document.write( "Thus x = -1/5 and y = 2\r<BR>\n" );
document.write( "\n" );
document.write( "Good Luck </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );