document.write( "Question 1049465: Tommy and Lisa leave their houses traveling in opposite direction on a straight road. Tommy drives 15 mph faster than Lisa. After 3 hours they are 225 miles apart. Find each rate \n" ); document.write( "
Algebra.Com's Answer #665004 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+s+\" = Lisa's speed in mi/hr
\n" ); document.write( "\"+s+%2B+15+\" = Tommy's speed in mi/hr
\n" ); document.write( "------------------------------------
\n" ); document.write( "Think of this as one of them standing still
\n" ); document.write( "and the other one moving at the sum of their speeds
\n" ); document.write( "\"+225+=+%28+s+%2B+s+%2B+15+%29%2A3+\"
\n" ); document.write( "\"+%28+2s+%2B+15+%29%2A3+=+225+\"
\n" ); document.write( "\"+6s+%2B+45+=+225+\"
\n" ); document.write( "\"+6s+=+180+\"
\n" ); document.write( "\"+s+=+30+\"
\n" ); document.write( "and
\n" ); document.write( "\"+s+%2B+15+=+45+\"
\n" ); document.write( "-------------------
\n" ); document.write( "Tommy's speed is 45 mi/hr
\n" ); document.write( "Lisa's speed is 30 mi/hr
\n" ); document.write( "----------------------------
\n" ); document.write( "check:
\n" ); document.write( "\"+d%5B1%5D+=+30%2A3+\"
\n" ); document.write( "\"+d%5B1%5D+=+90+\" mi
\n" ); document.write( "and
\n" ); document.write( "\"+d%5B2%5D+=+45%2A3+\"
\n" ); document.write( "\"+d%5B2%5D+=+135+\" mi
\n" ); document.write( "--------------------
\n" ); document.write( "\"+d%5B1%5D+%2B+d%5B2%5D+=+90+%2B+135+\"
\n" ); document.write( "\"+d%5B1%5D+%2B+d%5B2%5D+=+225+\" mi
\n" ); document.write( "OK
\n" ); document.write( "
\n" );