document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1049444>Question 1049444</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two planes, which are <BR>\n" );
document.write( "2235 miles apart, fly toward each other.  Their speeds differ by 95 mph.  If they pass each other in 3 hours, what is the speed of each?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #664993 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=664993\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two planes, which are <BR>\n" );
document.write( "2235 miles apart, fly toward each other. Their speeds differ by 95 mph. If they pass each other in 3 hours, what is the speed of each?<BR>\n" );
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document.write( "Their closing speed is x + x+95 = 2x+95 mph<BR>\n" );
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document.write( "rate = distance/time<BR>\n" );
document.write( "2x+95 = 2235/3<BR>\n" );
document.write( "2x + 95 = 745<BR>\n" );
document.write( "2x = 650<BR>\n" );
document.write( "x = 325 mph (slower plane rate)<BR>\n" );
document.write( "x+95 = 420 mph (faster plane rate)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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