document.write( "Question 91561: A TOTAL OF 27,000 IS INVESTED , PART OF IT AT 12% PART OF IT AT 13%. THE TOTAL INTEREST AFTER A YEAR IS 3,385 . HOW MUCH WAS INVESTED AT EACH RATE? \n" ); document.write( "
Algebra.Com's Answer #66498 by stanbon(75887) ![]() You can put this solution on YOUR website! A TOTAL OF 27,000 IS INVESTED , PART OF IT AT 12% PART OF IT AT 13%. THE TOTAL INTEREST AFTER A YEAR IS 3,385 . HOW MUCH WAS INVESTED AT EACH RATE? \n" ); document.write( "-------------- \n" ); document.write( "Let amount invested at 12% be \"x\"; amount of interest is 0.12x dollars \n" ); document.write( "------------ \n" ); document.write( "Amount invested at 13% is 27000-x; amount of int is 0.13(27000-x)=3510-0.13x dollars \n" ); document.write( "----------------------------- \n" ); document.write( "EQUATION: \n" ); document.write( "interest + interest = 3385 \n" ); document.write( "0.12x + 3510-0.13x = 3385 \n" ); document.write( "-0.01x = -125 \n" ); document.write( "x = $12,500 (amount invested at 12%) \n" ); document.write( "27000-12500 = $14,500 (amount invested at 13%) \n" ); document.write( "============ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |