document.write( "Question 1049329: Hi
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document.write( "joey had some 20cent and ten cent coins.when she used one third of them she hsd $9.60 left. She used half as many 20cent coins as tencent coins.\r
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document.write( "how many 10cent and 20cents coins did she use.\r
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document.write( "thanks \n" );
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Algebra.Com's Answer #664971 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! let t = no. of 20 cent coins \n" ); document.write( "let d = no. of 10 cent coins \n" ); document.write( ": \n" ); document.write( "Do this in cents, $9.60 = 960 cents \n" ); document.write( ": \n" ); document.write( "joey had some 20cent and ten cent coins. \n" ); document.write( "when she used one third of them she hsd $9.60 left. \n" ); document.write( "Then she has 2/3 left, therefore \n" ); document.write( " \n" ); document.write( "Multiply by 3, to get rid of the fraction \n" ); document.write( "2(20t + 10d) = 3(960) \n" ); document.write( "40t + 20d = 2880 \n" ); document.write( ": \n" ); document.write( "She used half as many 20cent coins as ten cent coins: \n" ); document.write( "t = \n" ); document.write( "d = 2t \n" ); document.write( ": \n" ); document.write( "how many 10cent and 20cents coins did she use. \n" ); document.write( "In the 1st equation, replace d with 2t \n" ); document.write( "40t + 20(2t) = 2880 \n" ); document.write( "40t + 40t = 2880 \n" ); document.write( "t = 2880/80 \n" ); document.write( "t = 36 ea 20 cent coins \n" ); document.write( "then \n" ); document.write( "d = 2(36) \n" ); document.write( "d = 72 ea 10 cent coins \n" ); document.write( ": \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "See if this checks out \n" ); document.write( ".20(36) + .10(72) = 14.40 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |