document.write( "Question 1049329: Hi
\n" ); document.write( "joey had some 20cent and ten cent coins.when she used one third of them she hsd $9.60 left. She used half as many 20cent coins as tencent coins.\r
\n" ); document.write( "\n" ); document.write( "how many 10cent and 20cents coins did she use.\r
\n" ); document.write( "\n" ); document.write( "thanks
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Algebra.Com's Answer #664971 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
let t = no. of 20 cent coins
\n" ); document.write( "let d = no. of 10 cent coins
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\n" ); document.write( "Do this in cents, $9.60 = 960 cents
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\n" ); document.write( "joey had some 20cent and ten cent coins.
\n" ); document.write( "when she used one third of them she hsd $9.60 left.
\n" ); document.write( "Then she has 2/3 left, therefore
\n" ); document.write( "\"2%2F3\"(20t + 10d) = 960
\n" ); document.write( "Multiply by 3, to get rid of the fraction
\n" ); document.write( "2(20t + 10d) = 3(960)
\n" ); document.write( "40t + 20d = 2880
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\n" ); document.write( "She used half as many 20cent coins as ten cent coins:
\n" ); document.write( "t = \"1%2F2\"d
\n" ); document.write( "d = 2t
\n" ); document.write( ":
\n" ); document.write( "how many 10cent and 20cents coins did she use.
\n" ); document.write( "In the 1st equation, replace d with 2t
\n" ); document.write( "40t + 20(2t) = 2880
\n" ); document.write( "40t + 40t = 2880
\n" ); document.write( "t = 2880/80
\n" ); document.write( "t = 36 ea 20 cent coins
\n" ); document.write( "then
\n" ); document.write( "d = 2(36)
\n" ); document.write( "d = 72 ea 10 cent coins
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\n" ); document.write( "See if this checks out
\n" ); document.write( ".20(36) + .10(72) = 14.40
\n" ); document.write( "\"2%2F3\"*14.40 = $9.60
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