document.write( "Question 1049367: The length of a rectangle is 5 less than twice its width. The perimeter is 26 meters. Find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #664959 by addingup(3677)\"\" \"About 
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2L+2W = 26 (1)
\n" ); document.write( "and
\n" ); document.write( "L = 2W-5 Substitute for L on (1)
\n" ); document.write( "2(2W-5)+2W = 26
\n" ); document.write( "4W-10+2W = 26
\n" ); document.write( "6W = 36
\n" ); document.write( "W = 6
\n" ); document.write( ">>>>>>>>>>>>>>
\n" ); document.write( "Check:
\n" ); document.write( "2(6)-5 = 7 this, according to the problem, is the length. Now:
\n" ); document.write( "2(7)+2(6) = 26
\n" ); document.write( "14+12 = 26 Correct
\n" ); document.write( ":
\n" ); document.write( "John
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