document.write( "Question 1049367: The length of a rectangle is 5 less than twice its width. The perimeter is 26 meters. Find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #664959 by addingup(3677)![]() ![]() You can put this solution on YOUR website! 2L+2W = 26 (1) \n" ); document.write( "and \n" ); document.write( "L = 2W-5 Substitute for L on (1) \n" ); document.write( "2(2W-5)+2W = 26 \n" ); document.write( "4W-10+2W = 26 \n" ); document.write( "6W = 36 \n" ); document.write( "W = 6 \n" ); document.write( ">>>>>>>>>>>>>> \n" ); document.write( "Check: \n" ); document.write( "2(6)-5 = 7 this, according to the problem, is the length. Now: \n" ); document.write( "2(7)+2(6) = 26 \n" ); document.write( "14+12 = 26 Correct \n" ); document.write( ": \n" ); document.write( "John \n" ); document.write( " |