document.write( "Question 1049373: A car travels 355 miles by going one speed for 3 hours and another speed for 4 hours. if it travels 3 hours at the second speed and 4 hours at the first speed, it would have gone 345 miles. find the two speeds. \n" ); document.write( "
Algebra.Com's Answer #664951 by advanced_Learner(501)\"\" \"About 
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the equations are
\n" ); document.write( "\"355\"=\"3x%2B4y\"
\n" ); document.write( "\"345\"=\"4x%2B3y\"\r
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Solved by pluggable solver: SOLVE linear system by SUBSTITUTION
Solve:
\n" ); document.write( " \"+system%28+%0D%0A++++3%5Cx+%2B+4%5Cy+=+355%2C%0D%0A++++4%5Cx+%2B+3%5Cy+=+345+%29%0D%0A++\"We'll use substitution. After moving 4*y to the right, we get:
\n" ); document.write( " \"3%2Ax+=+355+-+4%2Ay\", or \"x+=+355%2F3+-+4%2Ay%2F3\". Substitute that
\n" ); document.write( " into another equation:
\n" ); document.write( " \"4%2A%28355%2F3+-+4%2Ay%2F3%29+%2B+3%5Cy+=+345\" and simplify: So, we know that y=55. Since \"x+=+355%2F3+-+4%2Ay%2F3\", x=45.
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\n" ); document.write( " Answer: \"system%28+x=45%2C+y=55+%29\".
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