document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1049373>Question 1049373</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A car travels 355 miles by going one speed for 3 hours and another speed for 4 hours. if it travels 3 hours at the second speed and 4 hours at the first speed, it would have gone 345 miles. find the two speeds. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #664926 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=664926\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let m be the first speed, and n be the second. Then:<BR>\n" );
document.write( "3m+4n=355<BR>\n" );
document.write( "4m+3n=345. So:<BR>\n" );
document.write( "16m+12n=1380<BR>\n" );
document.write( "9m+12n=1065<BR>\n" );
document.write( "7m=315<BR>\n" );
document.write( "m=45 mph<BR>\n" );
document.write( "n=55 mph. &#9786;&#9786;&#9786;&#9786;<BR>\n" );
document.write( " </SPAN>\n" );
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