document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1049385>Question 1049385</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jan's age is 3 years less than twice Tritt`s age. The sum of their ages is 30.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #664908 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=664908\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let t represent Tritt. Then Jan would be 2t-3. So:<BR>\n" );
document.write( "t+2t-3=30<BR>\n" );
document.write( "3t=33<BR>\n" );
document.write( "t=11<BR>\n" );
document.write( "Tritt is 11; Jan is 19. &#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
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