document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1049272>Question 1049272</A>: <I><SPAN STYLE=\"word-break: break-all;\">  Find the diameter of a circle whose area as 112 cm² round your answer to the nearest 10th  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #664902 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=664902\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> formula for area of a circle is a = pi * r^2.\r<BR>\n" );
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document.write( "a is the area<BR>\n" );
document.write( "pi is 3.14.....<BR>\n" );
document.write( "r is the radius.<BR>\n" );
document.write( "d is the diameter.\r<BR>\n" );
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document.write( "the diameter is equal to twice the length of the radius.\r<BR>\n" );
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document.write( "a = pi * r^2.<BR>\n" );
document.write( "since a = 112, the formula becomes 112 = pi * r^2.<BR>\n" );
document.write( "divide both sides of this equation by pi to get:<BR>\n" );
document.write( "112/pi = r^2<BR>\n" );
document.write( "take the square root of both sides of this equation and solve for r to get:<BR>\n" );
document.write( "r = plus or minus sqrt(112/pi)<BR>\n" );
document.write( "the radius can't be minus, so you get:<BR>\n" );
document.write( "r = sqrt(112/pi)<BR>\n" );
document.write( "since diameter = twice the radius, you get:<BR>\n" );
document.write( "d = 2 * r which makes d = 2 * sqrt(112)/pi)<BR>\n" );
document.write( "solve for d to get d = 11.94164264<BR>\n" );
document.write( "round to 1 decimal place to get d = 11.9\r<BR>\n" );
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