document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1049345>Question 1049345</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A church spire 82 cm high cast a shadow 62 meters long. find the angle of elevation of the sun at that moment. Draw the diagram also. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #664896 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=664896\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The base of the right triangle is the length of the shadow: 62<BR>\n" );
document.write( "The height of the church spiral is the long leg of the right triangle: 82<BR>\n" );
document.write( "The other leg, the hypotenuse, goes from the end of the shadow to the top of the spire, this is the tangent and is the angle you want:<BR>\n" );
document.write( "SOHCAHTOA Since we know the Opposite (the base or short leg) and the Adjacent (long leg) we apply TOA: Tangent = Opposite/Adjacent.<BR>\n" );
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document.write( "Tan(x) = 62/82 both are divisible by 2, simplify:<BR>\n" );
document.write( "Tan(x) = 31/41<BR>\n" );
document.write( "x = Tan^(-1)(41/31) this is the inverse tan, look for the tan^-1 or arctan key in your calculator (mine has a tan^-1 key)<BR>\n" );
document.write( "x = Tan^-1(41/31) = 52.9 is your answer </SPAN>\n" );
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