document.write( "Question 1049347: The sum of two numbers is 160. Their difference is 38. Find the Numbers.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Help me please!!
\n" ); document.write( "

Algebra.Com's Answer #664881 by advanced_Learner(501)\"\" \"About 
You can put this solution on YOUR website!
The ruling equations are
\n" ); document.write( "\"a%2Bb\"=\"160\"
\n" ); document.write( "\"a-b\"=\"38\"\r
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: SOLVE linear system by SUBSTITUTION
Solve:
\n" ); document.write( " \"+system%28+%0D%0A++++1%5Ca+%2B+1%5Cb+=+160%2C%0D%0A++++1%5Ca+%2B+-1%5Cb+=+38+%29%0D%0A++\"We'll use substitution. After moving 1*b to the right, we get:
\n" ); document.write( " \"1%2Aa+=+160+-+1%2Ab\", or \"a+=+160%2F1+-+1%2Ab%2F1\". Substitute that
\n" ); document.write( " into another equation:
\n" ); document.write( " \"1%2A%28160%2F1+-+1%2Ab%2F1%29+%2B+-1%5Cb+=+38\" and simplify: So, we know that b=61. Since \"a+=+160%2F1+-+1%2Ab%2F1\", a=99.
\n" ); document.write( "
\n" ); document.write( " Answer: \"system%28+a=99%2C+b=61+%29\".
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" );