document.write( "Question 1049334: 1.Find the point P on the curve y = x^2 - 2x + 3, where the tangent is parallel to x-axis.\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #664869 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
This asks for the vertex, in other words. Why? The curve is a parabola with its minimum as the vertex and because of symmetry at the vertex, tangent on the curve will have slope 0 there.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "A bit of Calculus: \"dy%2Fdx=2x-2=0\"
\n" ); document.write( "\"x-1=0\"
\n" ); document.write( "\"x=1\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y=1%5E2-2%2A1%2B3\"
\n" ); document.write( "\"y=2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "P is (1,2).
\n" ); document.write( "
\n" );