document.write( "Question 1049302: Tangent (theta) + square root of 3 = secant (theta)\r
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Algebra.Com's Answer #664861 by ikleyn(52810)\"\" \"About 
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document.write( "So, you are trying to solve an equation\r\n" );
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document.write( "tan(x) + \"sqrt%283%29\" = sec(x).\r\n" );
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document.write( "It is the same as\r\n" );
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document.write( "\"sin%28x%29%2Fcos%28x%29\" + \"sqrt%283%29\" = \"1%2Fcos%28x%29\".\r\n" );
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document.write( "Multiply both sides by cos(x). You will get\r\n" );
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document.write( "\"sin%28x%29\" + \"sqrt%283%29%2Acos%28x%29\" = 1.\r\n" );
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document.write( "Multiply both sides by \"1%2F2\". You will get\r\n" );
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document.write( "\"%281%2F2%29%2Asin%28x%29\" + \"%28sqrt%283%29%2F2%29%2Acos%28x%29\" = \"1%2F2\".\r\n" );
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document.write( "Recall that \"1%2F2\" = \"cos%28pi%2F3%29\",  \"sqrt%283%29%2F2\" = \"sin%28pi%2F3%29\".\r\n" );
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document.write( "Therefore, you can write the last equation as \r\n" );
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document.write( "\"cos%28pi%2F3%29%2Asin%28x%29+%2B+sin%28pi%2F3%29%2Acos%28x%29\" = \"1%2F2\".\r\n" );
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document.write( "Apply the addition formula for sine.  ( It is cos(a)*sin(b) + sin(a)*cos(b) = sin(a+b). \r\n" );
document.write( "                                        See the lesson Addition and subtraction formulas in this site ). You will get\r\n" );
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document.write( "\"sin%28x+%2B+pi%2F3%29\" = \"1%2F2\".\r\n" );
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document.write( "It implies  \"x+%2B+pi%2F3\" = \"pi%2F6\"  or  \"x+%2B+pi%2F3\" = \"5pi%2F6\".\r\n" );
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document.write( "Hence,  x = \"pi%2F6-pi%2F3\" = \"-pi%2F6\"  or  x = \"5pi%2F6-pi%2F3\" = \"3pi%2F6\" = \"pi%2F2\".\r\n" );
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document.write( "The last root doesn't fit due to \"sec\" in the original equation.\r\n" );
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document.write( "Answer.  x = \"-pi%2F6\",  or  \"-pi%2F6+%2B+2k%2Api\" for any integer \"k\".\r\n" );
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\n" ); document.write( "\n" ); document.write( "See also the lessons\r
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