document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1049312>Question 1049312</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the circle passing through (-1, -3) and (-5, 3) and having its center on the line x-2y+2=0. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #664840 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39620)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=664840\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Center is on line <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x-2y%2B2=0 ALIGN=MIDDLE  ALT=\"x-2y%2B2=0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-2y=-x-2 ALIGN=MIDDLE  ALT=\"-2y=-x-2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=x%2F2%2B1 ALIGN=MIDDLE  ALT=\"y=x%2F2%2B1\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "and the center is some variable point ( x, x/2+1 ).\r<BR>\n" );
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document.write( "The two points ON the circle,  (-1,-3) and (-5,3) are equally distant from center point  ( x, x/2+1 ).  Can you decide how to use the DISTANCE FORMULA to find x, and then the corresponding y, for the coordinates of the center? </SPAN>\n" );
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