document.write( "Question 91529: Please help with solving this...I can't seem to get the fractional part correct.\r
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document.write( "One number exceeds another by 5. The sum of their reciprocals equal to 19 divided by the product of the two numbers. Find the two numbers. \n" );
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Algebra.Com's Answer #66481 by stanbon(75887) ![]() You can put this solution on YOUR website! Let one of the numbers be \"x\"; The other number is \"x+5\" \n" ); document.write( "EQUATION: \n" ); document.write( "1/x + 1/(x+5) = 19/x(x+5) \n" ); document.write( "Multiply thru by x(x+5) \n" ); document.write( "x+5 + x = 19 \n" ); document.write( "2x= 14 \n" ); document.write( "x = 7 (one of the numbers) \n" ); document.write( "x+5 = 12 (the other number) \n" ); document.write( "============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |