document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1049228>Question 1049228</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Near the surface of the moon, the distance that an object falls is a function of time. It is given by d(t) = 2.6667t^2, where t is in seconds and d(t) is in feet. If an object is dropped from a certain height, find the average speed of the object from t = 1 to t = 4. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #664806 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=664806\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> d = r*t so r = d/t<BR>\n" );
document.write( "d(1) = 2.6667(1)^2<BR>\n" );
document.write( "d(1) = 2.6667<BR>\n" );
document.write( "r = 2.6667/1 = 2.6667 is the speed, and in this case, where t=1, it is also the distance traveled in 1 second<BR>\n" );
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document.write( "d(4) = 2.6667(4)^2<BR>\n" );
document.write( "d(4) = 2.6667*16 = 42.6672 is the distance traveled in 4 seconds<BR>\n" );
document.write( "r = 42.6672/4 = 10.6668 is the speed per second\r<BR>\n" );
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