document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1049239>Question 1049239</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1/4 of a certain number is added to 4 1/3. The sum is same as when 1/3 of it ia added to 20 2/3. Find the number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #664803 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=664803\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/4x+4 1/3 = 1/3x+20 2/3<BR>\n" );
document.write( "1/4x+13/3 = 1/3x+62/3 subtract 1/3x and 13/3 on both sides<BR>\n" );
document.write( "1/4x-1/3x = 62/3-13/3<BR>\n" );
document.write( "3/12x-4/12x = 49/3<BR>\n" );
document.write( "-1/12x = 49/3 divide both sides by -1/12<BR>\n" );
document.write( "x = 49/3*-12/1<BR>\n" );
document.write( "x = -588/3 = -196 is your answer<BR>\n" );
document.write( ">>>>>>>>>>>>>>>>>>>>>>>>>>><BR>\n" );
document.write( "1/4(-196)+4 1/3 = 1/3(-196)+20 2/3<BR>\n" );
document.write( "-49+13/3 = (-196+62)/3<BR>\n" );
document.write( "(-147+13)/3 = (-196+62)/3<BR>\n" );
document.write( "-44 2/3 = -44 2/3 Correct<BR>\n" );
document.write( ":<BR>\n" );
document.write( "John<BR>\n" );
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