document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1049239>Question 1049239</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1/4 of a certain number is added to 4 1/3. The sum is same as when 1/3 of it ia added to 20 2/3. Find the number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #664788 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=664788\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/4 of a certain number is added to 4 1/3. The sum is same as when 1/3 of it is added to 20 2/3. Find the number. <BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "(1/4)x + 4 1/3 = (1/3)x + 20 2/3<BR>\n" );
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document.write( "Subtract (1/4)x from both sides to get::<BR>\n" );
document.write( "13/3 = [1/3 - 1/4]x + 62/3<BR>\n" );
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document.write( "[(4-3)/12]x = -49/3<BR>\n" );
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document.write( "(1/12)x = -49/3<BR>\n" );
document.write( "x = -588/3<BR>\n" );
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document.write( "x = -196<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );