document.write( "Question 1049189: Hi, could you please help me with this problem?\r
\n" );
document.write( "\n" );
document.write( "You take a sample of 22 from a population of test scores and the mean of your sample is 60. \r
\n" );
document.write( "\n" );
document.write( "(a) You know the standard deviation of the population is 10. What is the 99% confidence interval on the population mean. \r
\n" );
document.write( "\n" );
document.write( "(b) Now assume that you do not know the population standard deviation, but the standard deviation in your sample is 10. What is the 99% confidence interval on the mean now?\r
\n" );
document.write( "\n" );
document.write( "Thank you for your help \n" );
document.write( "
Algebra.Com's Answer #664785 by ewatrrr(24785) You can put this solution on YOUR website! For a population with unknown mean and known standard deviation , \n" ); document.write( "a confidence interval for the population mean is: CI = x̄ ± \n" ); document.write( "CI = = 60 ± \n" ); document.write( "CI = = 60 ± \n" ); document.write( "CI = = 60 ± 5.5 \n" ); document.write( "Or \n" ); document.write( "54.5 < \n" ); document.write( "b) \n" ); document.write( "For a population with unknown mean and unknown standard deviation , \n" ); document.write( "a confidence interval for the population mean is: CI = x̄ ± \n" ); document.write( "CI = 60 ± \n" ); document.write( "99% confidence level, Degree of Freedom(n-1) = 21: t = 2.831 (use Caculator 0r table) \n" ); document.write( "CI = 60 ± \n" ); document.write( "CI = 60 ± 6 \n" ); document.write( "0r \n" ); document.write( "54 < \n" ); document.write( "per TY \n" ); document.write( " ME = 6.0 for b and it equals 5.5 for a. Rounded t0 nearest tenth. \n" ); document.write( "Round as directed by Your Instructor \n" ); document.write( " |