document.write( "Question 1049232: A rectangle has a length of 6 and a width 5x+8 . The area is 80 . what is x ?
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Algebra.Com's Answer #664780 by MathLover1(20855)\"\" \"About 
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if a length of \"6\" and a width \"5x%2B8\", and the area is \"80\", we have\r
\n" ); document.write( "\n" ); document.write( "\"6%285x%2B8%29=80\"\r
\n" ); document.write( "\n" ); document.write( "\"30x%2B48=80\"\r
\n" ); document.write( "\n" ); document.write( "\"30x=80-48\"\r
\n" ); document.write( "\n" ); document.write( "\"30x=32\"\r
\n" ); document.write( "\n" ); document.write( "\"x=32%2F30\"\r
\n" ); document.write( "\n" ); document.write( "\"x=16%2F15\"\r
\n" ); document.write( "\n" ); document.write( "then a width is\r
\n" ); document.write( "\n" ); document.write( "\"5x%2B8=5%2816%2F15%29%2B8\"\r
\n" ); document.write( "\n" ); document.write( "\"5x%2B8=%2816%2F3%29%2B8\"\r
\n" ); document.write( "\n" ); document.write( "\"5x%2B8=16%2F3%2B24%2F3\"\r
\n" ); document.write( "\n" ); document.write( "\"5x%2B8=40%2F3\"\r
\n" ); document.write( "\n" ); document.write( "check the area:\r
\n" ); document.write( "\n" ); document.write( "\"length%2Awidth=80\"\r
\n" ); document.write( "\n" ); document.write( "\"6%2A%2840%2F3%29=80\"\r
\n" ); document.write( "\n" ); document.write( "\"cross%286%292%2A%2840%2Fcross%283%291%29=80\"\r
\n" ); document.write( "\n" ); document.write( "\"2%2A40=80\"\r
\n" ); document.write( "\n" ); document.write( "\"80=80\"\r
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