document.write( "Question 1049197: The parks department is planning a new flower bed outside city hall. It will be rectangular with dimensions 9m by 6m. The flower bed will be surrounded by a path of constant width with the same area as the flower bed. Calculate the perimeter of the outside of the path.
\n" ); document.write( "a) set up a quadratic equation to model the situation
\n" ); document.write( "b) use the quadratic formula to solve the problem
\n" ); document.write( "

Algebra.Com's Answer #664768 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
The parks department is planning a new flower bed outside city hall.
\n" ); document.write( " It will be rectangular with dimensions 9m by 6m.
\n" ); document.write( " The flower bed will be surrounded by a path of constant width with the same area as the flower bed.
\n" ); document.write( " Calculate the perimeter of the outside of the path.
\n" ); document.write( ":
\n" ); document.write( "the area of the flower bed: 9*6 = 54 sq/m, (also the area of the path)
\n" ); document.write( ":
\n" ); document.write( "a) set up a quadratic equation to model the situation
\n" ); document.write( "let w = the width of the path around the flower bed
\n" ); document.write( "then
\n" ); document.write( "(2w+9) by 2w+6) = the overall dimensions (garden and path)
\n" ); document.write( ":
\n" ); document.write( "the overall area - flower bed area = path area
\n" ); document.write( "(2w+9)*(2w+6) - 54 = 54
\n" ); document.write( "FOIL
\n" ); document.write( "4w^2 + 12w + 18w + 54 - 54 - 54 = 0
\n" ); document.write( "A quadratic equation
\n" ); document.write( "4w^2 + 30w - 54 = 0
\n" ); document.write( "simplify, divide by 2
\n" ); document.write( "2w^2 + 15w - 27 = 0
\n" ); document.write( ":
\n" ); document.write( "b) use the quadratic formula to solve the problem
\n" ); document.write( "2w^2 + 15w - 27 = 0; factors to:
\n" ); document.write( "(2w-3)(w+9) = 0
\n" ); document.write( "The positive solution is all we want here
\n" ); document.write( "2w = 3
\n" ); document.write( "w = 1.5 m is the width of the path
\n" ); document.write( ":
\n" ); document.write( "\"Calculate the perimeter of the outside of the path.\"
\n" ); document.write( "Find the overall dimensions
\n" ); document.write( "2(1.5) + 9 = 12m long
\n" ); document.write( "2(1.5) + 6 = 9m wide
\n" ); document.write( "P = 2(12) + 2(9)
\n" ); document.write( "p = 42 meters is the perimeter
\n" ); document.write( ":
\n" ); document.write( "
\n" ); document.write( "
\n" );