document.write( "Question 1049079: In his​ motorboat, Bill Ruhberg travels upstream at top speed to his favorite fishing​ spot, a distance of 528
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\n" ); document.write( "​mi, in 6
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\n" ); document.write( "hr.​ Returning, he finds that the trip​ downstream, still at top​ speed, takes only 5.5
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\n" ); document.write( "hr. Find the rate of​ Bill's boat and the speed of the current. Let x​ = the rate of the boat in still water and y​ = the rate of the current.
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Algebra.Com's Answer #664706 by advanced_Learner(501)\"\" \"About 
You can put this solution on YOUR website!
the required equations are \r
\n" ); document.write( "\n" ); document.write( "\"528%2F6\"=\"u-v\" for upstream
\n" ); document.write( "\"528%2F5.5\"=\"u%2Bv\" for downstream\r
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\n" ); document.write( "\n" ); document.write( "\"88\"=\"u-v\"
\n" ); document.write( "\"96\"=\"u%2Bv\"\r
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Solved by pluggable solver: SOLVE linear system by SUBSTITUTION
Solve:
\n" ); document.write( " \"+system%28+%0D%0A++++1%5Cu+%2B+-1%5Cv+=+88%2C%0D%0A++++1%5Cu+%2B+1%5Cv+=+96+%29%0D%0A++\"We'll use substitution. After moving -1*v to the right, we get:
\n" ); document.write( " \"1%2Au+=+88+-+-1%2Av\", or \"u+=+88%2F1+-+-1%2Av%2F1\". Substitute that
\n" ); document.write( " into another equation:
\n" ); document.write( " \"1%2A%2888%2F1+-+-1%2Av%2F1%29+%2B+1%5Cv+=+96\" and simplify: So, we know that v=4. Since \"u+=+88%2F1+-+-1%2Av%2F1\", u=92.
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\n" ); document.write( " Answer: \"system%28+u=92%2C+v=4+%29\".
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