document.write( "Question 1049065: A girl invested $10,000 for one year, part at 8% annual interest and the rest at 12% annual interest. her total interest for the year was $944. how much money did she invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #664620 by addingup(3677)![]() ![]() You can put this solution on YOUR website! Part at 8% = x \n" ); document.write( "Rest at 12% = 10,000-x, since x is invested at 8% \n" ); document.write( "0.08x+0.12(10,000-x) = 944 \n" ); document.write( "0.08x+1200-0.12x = 944 subtract 1200 from both sides \n" ); document.write( "0.08-0.12 = -256 Subtract on left \n" ); document.write( "-0.04x = -256 Divide both sides by -0.12 and remember -/- = + \n" ); document.write( "x = 6,400 this is how much is invested at 8%, and: \n" ); document.write( "10,000-6,400 = 3,600 is invested at 12% \n" ); document.write( " |