document.write( "Question 1048978: one number is four times another number. the third number is 5 more than the first number. their sum is 77. what are the numbers ? \n" ); document.write( "
Algebra.Com's Answer #664592 by ankor@dixie-net.com(22740)\"\" \"About 
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Three numbers; a, b, c
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\n" ); document.write( "Write an equation for each statement
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\n" ); document.write( "one number is four times another number.
\n" ); document.write( "a = 4b
\n" ); document.write( "divide both sides by 4 and you have
\n" ); document.write( "b = .25a
\n" ); document.write( " the third number is 5 more than the first number.
\n" ); document.write( "c = a + 5
\n" ); document.write( " their sum is 77.
\n" ); document.write( "a + b + c = 77
\n" ); document.write( "replace b, and c
\n" ); document.write( "a + .25a + (a+5) = 77
\n" ); document.write( "2.25a = 77 - 5
\n" ); document.write( "2.25a = 72
\n" ); document.write( "a = 72/2.25
\n" ); document.write( "a = 32 is the first number
\n" ); document.write( "then
\n" ); document.write( "b = .25(32)
\n" ); document.write( "b = 8 is the other number
\n" ); document.write( "and
\n" ); document.write( "c = 32 + 5
\n" ); document.write( "c = 37 is the 3rd number
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\n" ); document.write( "see if that checks out
\n" ); document.write( "32 + 8 + 37 = 77\r
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