document.write( "Question 91500: Can someone please help me solve this problem. I am having trouble understanding how to solve it.
\n" ); document.write( "3x+4y=12 with this solutions: (0, ),(2/3, ),( ,0),and (-2/3, ).
\n" ); document.write( "Thank you. \n" ); document.write( "
Algebra.Com's Answer #66458 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
3X+4Y=12 NOW SUBSTITUTE 0 FOR X & SOLVE FOR Y:
\n" ); document.write( "3*0+4Y=12
\n" ); document.write( "4Y=12
\n" ); document.write( "Y=12/4
\n" ); document.write( "Y=3 ANSWER IS (0,3)
\n" ); document.write( "3*2/3+4Y=12
\n" ); document.write( "6/3+4Y=12
\n" ); document.write( "2+4Y=12
\n" ); document.write( "4Y=12-2
\n" ); document.write( "4Y=10
\n" ); document.write( "Y=10/4
\n" ); document.write( "Y=5/2 ANSWER (2/3,5/2)
\n" ); document.write( "3X+4*0=12
\n" ); document.write( "3X=12
\n" ); document.write( "X=12/3
\n" ); document.write( "X=4 ANSWER (4,0)
\n" ); document.write( "3*-2/3+4Y=12
\n" ); document.write( "-6/3+4Y=12
\n" ); document.write( "-2+4Y=12
\n" ); document.write( "4Y=12+2
\n" ); document.write( "4Y=14
\n" ); document.write( "Y=14/4
\n" ); document.write( "Y=7/2 ANSWER (-2/3,7/2)
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+y+=+-3x%2F4+%2B3%29+\" (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = -3x/4 +3). \r
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