document.write( "Question 1048949: x=y+2
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Algebra.Com's Answer #664495 by ikleyn(52781)\"\" \"About 
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document.write( "x = y+2,     (1)\r\n" );
document.write( "2x+y = 1.    (2)\r\n" );
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document.write( "To solve this system, apply the Substitution method.\r\n" );
document.write( "You just have \"x\" expressed via \"y\" in the equation (1).\r\n" );
document.write( "Substitute it into the equation (2). Ypou will get\r\n" );
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document.write( "2*(y+2) + y = 1.\r\n" );
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document.write( "It is a single equation for \"y\". You just excluded \"x\".\r\n" );
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document.write( "Solve th equation (3) for \"y\":\r\n" );
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document.write( "2y + 4 + y =1,\r\n" );
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document.write( "3y = 1 - 4,\r\n" );
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document.write( "3y = -3,\r\n" );
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document.write( "y = \"%28-3%29%2F3\" = -1.\r\n" );
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document.write( "Thus you just found y. It is 1.\r\n" );
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document.write( "Now from (1) find x = y+2 = -1+2 = 1.\r\n" );
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document.write( "Answer.  x = 1,  y = -1.\r\n" );
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document.write( "Check it on your own.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Look into the lessons\r
\n" ); document.write( "\n" ); document.write( "    - Solution of a linear system of two equations in two unknowns by the Substitution method \r
\n" ); document.write( "\n" ); document.write( "    - Solution of a linear system of two equations in two unknowns by the Elimination method \r
\n" ); document.write( "\n" ); document.write( "    - Solution of a linear system of two equations in two unknowns using determinant \r
\n" ); document.write( "\n" ); document.write( "    - Geometric interpretation of a linear system of two equations in two unknowns \r
\n" ); document.write( "\n" ); document.write( "    - Solving word problems using linear systems of two equations in two unknowns \r
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