document.write( "Question 1048933: A chemical company makes two brands of antifreeze. The first brand is
\n" ); document.write( "55% pure antifreeze, and the second brand is 95% pure antifreeze. In order to obtain 160 gallons of a mixture that contains 85% pure antifreeze, how many gallons of each brand of antifreeze must be used?\r
\n" ); document.write( "\n" ); document.write( "I'm assuming x+y=160 and .55+.95=.85 but the answer doesn't make sense to me.
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Algebra.Com's Answer #664481 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+a+\" = gallons of 55% antifreeze needed
\n" ); document.write( "Let \"+b+\" = gallons of 95% antifreeze needed
\n" ); document.write( "-----------------------
\n" ); document.write( "(1) \"+a+%2B+b+=+160+\"
\n" ); document.write( "(2) \"+%28+.55a+%2B+.95b+%29+%2F+160+=+.85+\"
\n" ); document.write( "-----------------------------------
\n" ); document.write( "(2) \"+.55a+%2B+.95b+=+.85%2A160+\"
\n" ); document.write( "(2) \"+.55a+%2B+.95b+=+136+\"
\n" ); document.write( "(2) \"+55a+%2B+95b+=+13600+\"
\n" ); document.write( "(2) \"+11a+%2B+19b+=+2720+\"
\n" ); document.write( "----------------------------
\n" ); document.write( "Multiply both sides of (1) by \"+11+\"
\n" ); document.write( "and subtract (1) from (2)
\n" ); document.write( "(2) \"+11a+%2B+19b+=+2720+\"
\n" ); document.write( "(1) \"+-11a+-+11b+=+-1760+\"
\n" ); document.write( "---------------------------
\n" ); document.write( "\"+8b+=+960+\"
\n" ); document.write( "\"+b+=+120+\"
\n" ); document.write( "and
\n" ); document.write( "(1) \"+a+%2B+120+=+160+\"
\n" ); document.write( "(1) \"+a+=+40+\"
\n" ); document.write( "-------------------
\n" ); document.write( "40 gallons of 55% antifreeze are needed
\n" ); document.write( "120 gallons of 95% antifreeze are needed
\n" ); document.write( "--------------------------------------
\n" ); document.write( "check:
\n" ); document.write( "(2) \"+%28+.55a+%2B+.95b+%29+%2F+160+=+.85+\"
\n" ); document.write( "(2) \"+%28+.55%2A40+%2B+.95%2A120+%29+%2F+160+=+.85+\"
\n" ); document.write( "(2) \"+%28+22+%2B+114+%29+%2F+160+=+.85+\"
\n" ); document.write( "(2) \"+136+=+.85%2A160+\"
\n" ); document.write( "(2) \"+136+=+136+\"
\n" ); document.write( "OK
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